Woo, math.
To get you on the same wavelength, think of it this way: If you laid a sheet of glass on the ground, it would receive X amount of rainfall from the sky. If you move the sheet left or right along the ground, no matter how fast or where you move it (Assuming rain doesn't slide off), it will not collect any extra rain. If you move it to the left to catch a raindrop, it'll miss an equal raindrop on the right side.
HOWEVER: We can collect more rain by moving it along a different axis. Strap a rocket to it, shoot it directly up into the sky, and it will collect more rain based on it's speed. We're basically accelerating the relative speed of the rain by speeding up the glass.
Same thing if we take that same sheet of glass, and stand it up vertically. In a math world, rain falls perfectly vertically, so no rain will land on the flat side... But if we strap another rocket to it and shoot it across your yard, it will smash into falling rain as it moves, and get wet before crashing into your fence and exploding into a million shards.
So if we look at both of those cases, it is reasonable to assume that there is a middle ground between horizontal and vertical. Something like an angled piece of glass, and moving it in one direction or another would accelerate the rate at which it collides with rain. Where would you find an angled piece of glass that we can accelerate? Hmm...
Let's simplify it. You have a windshield, it is 1.41m x 1.41m, and at a 45 degree angle. 1.41 is a weird number, but it just means that our windshield has a cross section of 1 square meter on both the horizontal and vertical plane. The density of rainfall is one drop per cubic meter, evenly distributed and falling at 1 meter per second.
Sitting still, you will be hit by 1 rain drop per second. Density x rate x area.
Lets pretend you are now moving 10 m/s. 22.4 MPH, 36 km/h. We no longer care about the horizontal plane, we care about the vertical plane. And since the vertical plane is traveling, we add another variable to the equation! Speed. In one second, the vertical plane displaces 10 cubic meters of space, colliding with the 10 rain drops that were once occupying this space. Now, you guys are kinda right, the horizontal plane doesn't change, so from that perspective one rain drop falls on the car... But in that time, the car crashes into 10 rain drops.
Now, that's extremely exaggerated. In real life, rain falls faster than that, so the difference is less pronounced. A real world rain drop reaches terminal velocity at at 10 m/s, so traveling at 10 m/s would only result in a 2x increase in rain contacting the windshield. 1 rain drop falling on the wind shield from the horizontal plane, and your car colliding with one rain drop in it's 10 meters of forward movement.
Since I'm not the owner of a wind tunnel, I can't model how aerodynamics affect rainfall, but we can calculate roughly much extra rain will hit your car based on density, rate, area, and speed. (We're talking spherical cows here, good enough, but the real world is off by a bit)
Density (drops per cubic meter) * Rate (Your speed relative to rain, or the rain's speed relative to you. Same thing... In meters per second) * Area (Square meter cross sectional area of your windshield) = Rate of rain.
Lets say it's a crazy storm. 500 raindrops per cubic meter. It's falling at terminal velocity, 10 m/s, you have the perfect windshield as above, 1 square meter and you're moving at 78.3 MPH (35 meters per second).
Sitting still: you're collecting 500x10x1=5000 raindrops per second on the horizontal plane.
Driving at 78.3 mph: You're collecting 500x35x1= 17,500 raindrops per second on the vertical plane.
The math even works backwards. If we're falling from the sky at the same speed as the rain, we won't get wet at all. Right? 500x0x1=0 Raindrops per second.
Now, it's not perfect. We don't account for steeper windshields, we don't account for your car's slipstream, and we ignore angles and curves in the glass, but it illustrates that movement = more rain collision.
For those that still doubt, consider aerodynamic drag. The faster we move, the more air we displace, and the more power we need to overcome that. In a sufficiently dense rainfall, we would have to start considering
hydrodynamic drag. The faster we move, the more water we have to displace, and the more power we need to overcome that! You could technically be in such a heavy rainstorm that your top speed would be significantly reduced, but that effect on your car would be much lower at low speeds, because your car is running into less water.
Now, without being able to calculate the effects of your slipstream or the angle of the Stinger's windshield and the effects of it's curved edges, it's hard to get a good answer, but I would say it's safe to assume that a Stinger traveling at 80 mph is collecting 2-3x as much rain on it's windshield as a stopped one.